Free 1Z0-071 Exam Dumps

Question 16

Which three statements are true regarding single-row functions? (Choose three.)

A. The data type returned, can be different from the data type of the argument that is referenced.
B. They can return multiple values of more than one data type.
C. They can accept only one argument.
D. They can be nested up to only two levels.
E. They can be used in SELECT, WHERE, and ORDER BY clauses.
F. They can accept column names, expressions, variable names, or a user-supplied constants as arguments.

Correct Answer:AEF

Question 17

View and Exhibit and examine the structure and data in the INVOICE table. (Choose two.)
1Z0-071 dumps exhibit
Which two statements are true regarding data type conversion in query expressions?

A. inv_date = '15-february-2008' :uses implicit conversion
B. inv_amt = '0255982' : requires explicit conversion
C. inv_date > '01-02-2008' : uses implicit conversion
D. CONCAT(inv_amt, inv_date) : requires explicit conversion
E. inv_no BETWEEN '101' AND '110' : uses implicit conversion

Correct Answer:AE

Question 18

View the Exhibit and examine the structure of the PROMOTION table.
1Z0-071 dumps exhibit
You have to generate a report that displays the promo named start data for all promos that started after that last promo in the ‘INTTERNET’ category.

A. Select promo_name, promo_being_date FROM promoptions WHERE promo_being_data > ANY (SELCT promo_being-date FROM promotionsWHERE promo_category = ‘INTERNET’
B. SELECT promo_neme, promo_being_date FROM promotions WHERE promo_being_date > All (SELECT promo_beinjg-date FROM promotionsWHERE promo_category =’INTERNET’ );
C. SELECT promo-name, promo-being _date FROM promotionsWhere promo_being_data >ALL (SELECT MAX (promo_being-date) FROM promotions ) ANDPromo-category =’INTERNET’;
D. SELECT promo-name, promo-being_date FROM promotion WHERE promo-being-date IN (SELECT promo_biing_date FROM promotionsWHERE promo_category=’INTYERNET’);

Correct Answer:B

Question 19

View the exhibit and examine the structure of the STORES table. STORES table
NameNull?Type
---------------------- ------------- STORE_IDNUMBER NAMEVARCHAR2(100)
ADDRESSVARCHAR2(200) CITYVARCHAR2(100) COUNTRYVARCHAR2(100) START_DATEDATE END_DATEDATE PROPERTY_PRICENUMBER
You want to display the NAME of the store along with the ADDRESS, START_DATE, PROPERTY_PRICE, and the projected property price, which is 115% of property price.
The stores displayed must have START_DATE in the range of 36 months starting from 01-Jan-2000 and above.
Which SQL statement would get the desired output?

A. SELECT name, concat (address| | ','| |city| |', ', country) AS full_address,start_date,property_price, property_price*115/100FROM storesWHERE MONTHS_BETWEEN (start_date, '01-JAN-2000')<=36;
B. SELECT name, concat (address| | ','| |city| |', ', country) AS full_address,start_date,property_price, property_price*115/100FROM storesWHERETO_NUMBER(start_date-TO_DATE('01-JAN-2000','DD-MON-RRRR')) <=36;
C. SELECT name, address||','||city||','||country AS full_address,start_date,property_price, property_price*115/100FROM storesWHERE MONTHS_BETWEEN (start_date, TO_DATE('01-JAN-2000','DD-MON-RRRR')) <=36;
D. SELECT name, concat (address||','| |city| |', ', country) AS full_address,start_date,property_price, property_price*115/100FROM storesWHERE MONTHS_BETWEEN (start_date, TO_DATE('01-JAN-2000','DD-MON-RRRR')) <=36;

Correct Answer:D

Question 20

You must create a table EMPLOYEES in which the values in the columns EMPLOYEES_ID and LOGIN_ID must be unique and not null. (Choose two.)
Which two SQL statements would create the required table?

A. CREATE TABLE employees(employee_id NUMBER,Login_id NUMBER,Employee_name VARCHAR2(100),Hire_date DATE,CONSTRAINT emp_id_ukUNIQUE (employee_id, login_id));
B. CREATE TABLE employees(employee_id NUMBER,login_id NUMBER,employee_name VARCHAR2(25),hire_date DATE,CONSTRAINT emp_id_pk PRIMARY KEY (employee_id, login_id));
C. CREATE TABLE employees(employee_id NUMBER CONSTRAINT emp_id_pk PRIMARY KEY, Login_id NUMBER UNIQUE, Employee_name VARCHAR2(25),Hire_date DATE);
D. CREATE TABLE employees(employee_id NUMBER,Login_id NUMBER,Employee_name VARCHAR2(100),Hire_date DATE,CONSTRAINT emp_id_uk UNIQUE (employee_id, login_id);CONSTRAINT emp_id_nn NOT NULL (employee_id, login_id));
E. CREATE TABLE employees(employee_id NUMBER CONSTRAINT emp_id_nn NOT NULL, Login_id NUMBER CONSTRAINT login_id_nn NOT NULL,Employee_name VARCHAR2(100),Hire_date DATE,CONSTRAINT emp_id_ukUNIQUE (employee_id, login_id));

Correct Answer:BE