Free 1Z0-071 Exam Dumps

Question 36

You execute the SQL statement: SQL> CREATE TABLE citizens
(citizen_id CHAR (10) PRIMARY KEY, last_name VARCHAR2 (50) NOT NULL, first_name VARCHAR2 (50),
address VARCHAR2 (100),
city VARCHAR2 (30) DEFAULT ‘SEATTLE’ NOT NULL,
CONSTRAINT cnames CHECK (first_name<>last_name) ); What is the outcome?

A. It fails because the NOT NULL and DEFAULT options cannot be combined for the same column.
B. It succeeds and CITY can contain only ‘SEATTLE’ or null for all rows.
C. It fails because the condition for the CANAMES constraint is not valid.
D. It succeeds and an index is crated for CITIZEN_ID.

Correct Answer:A

Question 37

View the exhibit and examine the structure of the SALES, CUSTOMERS, PRODUCTS and TIMES tables.
1Z0-071 dumps exhibit
The PROD_ID column is the foreign key in the SALES tables, which references the PRODUCTS table.
Similarly, the CUST_ID and TIME_ID columns are also foreign keys in the SALES table referencing the CUSTOMERS and TIMES tables, respectively.
Evaluate the following CREATE TABLE command:
CREATE TABLE new_sales (prod_id, cust_id, order_date DEFAULT SYSDATE)
AS
SELECT prod_id, cust_id, time_id FROM sales;
Which statement is true regarding the above command?

A. The NEW_SALES table would get created and all the NOT NULL constraints defined on the specified columns would be passed to the new table.
B. The NEW_SALES table would not get created because the DEFAULT value cannot be specified in the column definition.
C. The NEW_SALES table would not get created because the column names in the CREATE TABLE command and the SELECT clause do not match.
D. The NEW_SALES table would get created and all the FOREIGN KEY constraints defined on the specified columns would be passed to the new table.

Correct Answer:A

Question 38

Which statement is true about an inner join specified in the WHERE clause of a query?

A. It must have primary-key and foreign-key constraints defined on the columns used in the join condition.
B. It requires the column names to be the same in all tables used for the join conditions.
C. It is applicable for equijoin and nonequijoin conditions.
D. It is applicable for only equijoin conditions.

Correct Answer:C

Question 39

View the exhibit and examine the structure of the CUSTOMERS table.
1Z0-071 dumps exhibit
Which two tasks would require subqueries or joins to be executed in a single statement?

A. finding the number of customers, in each city, whose credit limit is more than the average credit limit of all the customers
B. finding the average credit limit of male customers residing in 'Tokyo' or 'Sydney'
C. listing of customers who do not have a credit limit and were born before 1980
D. finding the number of customers, in each city, who’s marital status is 'married'.
E. listing of those customers, whose credit limit is the same as the credit limit of customers residing in the city 'Tokyo'.

Correct Answer:AE

Question 40

View the exhibit and examine the structure of ORDERS and CUSTOMERS tables. ORDERS
Name Null? Type
ORDER_ID NOT NULL NUMBER(4) ORDER_DATE NOT NULL DATE ORDER_MODE VARCHAR2(8) CUSTOMER_ID NOT NULL NUMBER(6) ORDER_TOTAL NUMBER(8, 2) CUSTOMERS
Name Null? Type
CUSTOMER_ID NOT NULL
NUMBER(6) CUST_FIRST_NAME NOT NULL VARCHAR2(20) CUST_LAST_NAME NOT NULL VARCHAR2(20) CREDIT_LIMIT NUMBER(9,2) CUST_ADDRESS VARCHAR2(40)
Which INSERT statement should be used to add a row into the ORDERS table for the customer whose CUST_LAST_NAME is Roberts and CREDIT_LIMIT is 600? Assume there exists only one row with CUST_LAST_NAME as Roberts and CREDIT_LIMIT as 600.

A. INSERT INTO (SELECT o.order_id, o.order_date, o.order_mode, c.customer_id, o.order_totalFROM orders o, customers cWHERE o.customer_id = c.customer_id AND c.cust_last_name='Roberts' AND c.credit_limit=600)VALUES (1,'10-mar-2007', 'direct', (SELECT customer_idFROM customersWHERE cust_last_name='Roberts' AND credit_limit=600), 1000);
B. INSERT INTO orders (order_id, order_date, order_mode,(SELECT customer idFROM customersWHERE cust_last_name='Roberts' AND credit_limit=600), order_total);VALUES (1,'10-mar-2007', 'direct', &customer_id, 1000);
C. INSERT INTO ordersVALUES (1,'10-mar-2007', 'direct',(SELECT customer_idFROM customersWHERE cust_last_name='Roberts' AND credit_limit=600), 1000);
D. INSERT INTO orders (order_id, order_date, order_mode,(SELECT customer_idFROM customersWHERE cust_last_name='Roberts' AND credit_limit=600), order_total);VALUES (1,'10-mar-2007', 'direct', &customer_id, 1000);

Correct Answer:C